Javascript: Search String In Array Then Count Occurrences

I am using indexOf to search for a string in an array, how can I continue to count the number of occurences? I tried the latter but it isn't working. var feed= new Array(); var fee

Solution 1:

You can set a count variable and iterate over the elements of feed. Then check if the element has indexOf unequal -1 (means found) and count the occurence.

var feed = ["testABC", "test", "testABC"],
    count = 0,
    i;

for (i = 0; i < feed.length; i++) {
    if (feed[i].indexOf("testABC") !== -1) {
        count++;
    }
}

console.log(count);

Solution 2:

Try to use Array.prototype.forEach function:

var feed  = ['foo','testABC','bar','testABC','testABC'];
var count = 0;
feed.forEach(function(value){
    if(value=='testABC') count++;
});
console.log(count); //3

Or Array.prototype.filter function:

var feed  = ['foo','testABC','bar','testABC','testABC'];
var count = feed.filter( function(value) { return value=='testABC' } ).length;
console.log(count); //3

Solution 3:

var numOfString = 0;
var feed= newArray()
var feed= ["testABC", "test", "testABC"]

for(var i=0;i<feed.length;i++){
    if(feed[i] === "testABC")
       numOfString++;
}
console.log(numOfString);

Solution 4:

Here's a simple and straight forward solution. You may want to make it a function in the case that you want to reuse your code.

var feed= newArray()
var feed= ["testABC", "test", "testABC"]
var count = 0// ensure that our array contains the key you want prior to scanning itif(feed.findIndex("testABC") >= 0) {
    for (var i=0; i < feed.length; i++ ) { 
    if(feed[i] === "testABC") count++
  }
}

alert(count)

Solution 5:

In addition to all the ways the other stated, if you are using ES6 you can use the 'for of' loop to iterate all the array's values:

var numOfString = 0;
var feed = ["testABC", "test", "testABC"];
for(let currentString of feed) {
  if(currentString.indexOf('testABC') !== -1) {
    numOfString += 1;
  }
}
console.log(numOfString);