Regular Expression Match All Except First Occurence

I need a regular expression to match all occurrences of a dot (.) except the first one. For example if the source is: aaa.bbb.ccc..ddd the expression should match the dots after b

Solution 1:

with pcre (PHP, R) you can do that:

\G(?:\A[^.]*\.)?+[^.]*\K\.

demo

details:

\G # anchor for the start of the string or the position after a previous match
(?:\A[^.]*\.)?+# start of the string (optional possessive quantifier)
[^.]* # all that is not a dot
\K    # remove all that has been matched on the left from the match result
\.    # the literal dot

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With .net: (easy since you can use a variable length lookbehind)

(?<!^[^.]*)\.

demo

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With javascript there is no way to do it with a single pattern.

using a placeholder:

var result = s.replace('.', 'PLACEHOLDER')
              .replace(/\./g, '|')
              .replace('PLACEHOLDER', '.');

(or replace all dots with | and then replace the first occurrence of | with a dot).

using split:

var parts = s.split('.');
var result = parts.shift() + (parts.length ? '.': '') + parts.join('|');

with a counter:

var counter = 0;
var result = s.replace(/\./g, (_) => counter++ ? '|' : '.');

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With NodeJS (or any other implementation that allows lookbehinds):

var result = s.replace(/((?:^[^.]*\.)?(?<=.)[^.]*)\./g, "$1|");

Solution 2:

One-line solution for JavaScript using arrow function (ES6):

'aaa.bbb.ccc..ddd'
   .replace(/\./g, (c, i, text) => text.indexOf(c) === i ? c : '|')

-> 'aaa.bbb|ccc||ddd'